Bombs - Affinity Laws

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The affinity laws of turbo machines can be used to calculate volume capacity, head or power consumption in centrifugal pumps when changing speed or wheel diameters.

Off With Him Affinity score of centrifugal pumps or fans indicates the influence on the volume capacity, head (pressure) and/or energy consumption of a bomba or fan due to

  • change in speed wheel – revolutions per minute (rpm)
  • geometric similarity – change in impeller diameter

Note that there are two sets of affinity laws:

  • affinity laws for a specific centrifugal pump – to approximate height, capacity and power curves for different motor speeds and/or different impeller diameters
  • Affinity laws for a family of geometrically similar centrifugal pumps – to approximate load, capacity and power curves for different motor speeds and/or different rotor diameters

Pump affinity laws for a specific centrifugal pump

Volume Capacity

The volumetric capacity of a centrifugal pump can be expressed as

q 1 / q 2 = (n 1 / n 2 ) (d 1 / d 2 ) (1)

Where

q = volume flow capacity (m 3 /s, gpm, cfm, ..)

n = wheel speed – rotation per minute – (rpm)

d = wheel diameter (m, feet)

Head or Pressure

The head or pressure of a centrifugal pump can be expressed as

dp 1 / dp 2 = (n 1 / n 2 ) 2 (d 1 / d 2 ) 2 (2)

Where

dp = load or pressure (m, ft, Pa, psi, ..)

Can

The energy consumption of a centrifugal pump can be expressed as

P 1 / P 2 = (n 1 / n 2 ) 3 (d 1 / d 2 ) 3 (3)

Where

P = power (W, bhp, ..)

Changing Wheel Speed

leis de afinidade de bombas centrífugas

I know wheel diameter is constant – changing the speed of the pump wheel can simplify the affinity laws for

Volume Capacity

q 1 / q 2 = (n 1 / n 2 ) (1a)

Head or Pressure

dp 1 / dp 2 = (n 1 / n 2 ) 2 (2a)

Can

P 1 / P 2 = (n 1 / n 2 ) 3 (3a)

leis de afinidade da bomba - mudando o diagrama de velocidade da roda

Observation! If the speed of a pump is increased by 10%

  • volume flow increases with 10%
  • the head increases with 21%
  • power increases with 33%

If we want to increase the flow capacity of an existing system in 10% , we have to increase the power supply by 33% .

Changing the Impeller Diameter

If the wheel speed is constant, a change in rotor diameter simplifies affinity laws to

Volume Capacity

q 1 / q 2 = d 1 / d 2 (1b)

Head or Pressure

dp 1 / dp 2 = (d 1 / d 2 ) 2 (2b)

Can

P 1 / P 2 = (d 1 / d 2 ) 3 (3B)

leis de afinidade da bomba - mudando o diagrama do diâmetro da roda

Example – Pump Affinity Laws – Changing Pump Speed

The pump speed changes when the impeller size is constant. The initial flow is 100 gpm , the initial head is 100 feet , the initial power is the 5 bhp , the initial speed is 1750 rpm and the final speed of 3500 rpm .

The final flow capacity can be calculated with (1a):

q 2 = q 1 n 2 / n 1

= (100 gpm) (3500 rpm) / (1750 rpm)

= 200 gpm

The final head can be calculated with (2a):

dp 2 = dp 1 (n 2 / n 1 ) 2

= (100 feet) ((3500 rpm) / (1750 rpm)) 2

= 400 feet

The final energy consumption can be calculated with (3a):

P 2 = P 1 (n 2 / n 1 ) 3

= (5 cv) ((3500 rpm) / (1750 rpm)) 3

= 40 cv

Example – Pump Affinity Laws – Impeller Diameter Change

The diameter of the pump impeller is reduced when the pump speed is constant. The diameter is changed from 8 to 6 inches .

The final flow capacity can be calculated with (1b) :

q 2 = q 1 (d 2 / d 1 )

= (100 gpm) ((¨6 in) / (8 in))

= 75 gpm

The final head can be calculated with (2b) :

dp 2 = dp 1 (d 2 / d 1 ) 2

= (100 ft) ((6 pol) / (8 pol)) 2

= 56.3 feet

The final energy consumption can be calculated with (3B) :

P 2 = P 1 (d 2 / d 1 ) 3

= (5 cv) ((6 half) / (8 half)) 3

= 2,1 cv

Bomb affinity laws for a family of geometrically similar bombs

Volume capacity can be expressed as

q 1 / q 2 = (n 1 / n 2 )(d 1 / d 2 ) 3 (4)

Where

q = volume flow capacity (m 3 /s, gpm, cfm, ..)

n = wheel speed – rotation per minute – (rpm)

d = wheel diameter

Head or Pressure

The head or pressure of a centrifugal pump can be expressed as

dp 1 / dp 2 = (n 1 / n 2 ) 2 (d 1 / d 2 ) 2 (5)

Where

dp = load or pressure (m, ft, Pa, psi, ..)

Can

The energy consumption of a centrifugal pump can be expressed as

P 1 / P 2 = (n 1 / n 2 ) 3 (d 1 / d 2 ) 5 (6)

Where

P = power (W, bhp, ..)

Note that the affinity laws for fans are not identical to pumps.

Source: https://www.engineeringtoolbox.com/affinity-laws-d_408.html

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